How does lambda build up the world?
Last update: December 7, 2024 pm
Everything is Function
In pure math, there is no transistors, so we cannot build any gates and storage media. For such tasks, we introduce the Church Encoding.
Boolean Algebra Revisit
Boolean is a value that is either true or false. Algebra somehow means functions. Are Boolean functions?
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This syntax is supported in most programming languages.
That is, we use the boolean condition to select between two values.
If the condition is true, we select val1
,
otherwise we select val2
.
Let’s write functions that do these things. Let function true as $T$ takes choose the first among its two inputs, $$ T = \lambda ab. a = K $$ then it’s just the Kestrel defined in last post! Then define false as $F$ which returns the second input, $$ F = \lambda ab.b = KI $$ which is the Kite.
Now the question is about the other boolean logics.
The first and the most important is negation,
the !
in most programming languages.
Come to think about this,
the function $\mathrm{Not}$ takes one boolean input and return the negation of it.
That is,
- if the input is true (select the first), we return false;
- if the input is false (select the second), we return true.
Then we can define $$ \mathrm{Not} = \lambda p. pFT $$ and if we express the idea of $N$ verbosely $$\begin{align} \mathrm{Not}\ T & = F \leftrightarrow \lambda (\lambda ab.a) . (\lambda ba.a) \\ \mathrm{Not}\ F & = T \leftrightarrow \lambda (\lambda ba.a) . (\lambda ab.a) \end{align}$$ we can see $Not$ is doing reverse application! Negation is just the Cardinal!
To find the $\mathrm{And}$ function, we can look at the truth table of and first
$x$ | $y$ | $\mathrm{And}\ x y$ |
---|---|---|
T | T | T |
T | F | F |
F | T | F |
F | F | F |
There are two cases:
- If $x$ is true, then $\mathrm{And}\ xy = y$;
- If $x$ is false, then $\mathrm{And}\ xy = F$.
Therefore, the $\mathrm{And}$ may involve some function that choose between two inputs. Recall that $T$ and $F$ are the two functions choosing between inputs! And $T$ and $F$ are the possible candidates of $\mathrm{And}$! Let $$ \mathrm{And} = \lambda xy. xyF $$ then $\mathrm{And}$ satisfies the description above.
Think about the case when $x$ is false, can we have another definition of $\mathrm{And}$?
$x$ | $y$ | $\mathrm{Or}\ x y$ |
---|---|---|
T | T | T |
T | F | T |
F | T | T |
F | F | F |
$\mathrm{Or}$ is very similar to $\mathrm{And}$.
- If $x$ is true, then $\mathrm{Or}\ xy = T$;
- If $x$ is false, then $\mathrm{Or}\ xy = y$.
Then we can give the $\mathrm{Or}$ function $$ \mathrm{Or} = \lambda xy. xTy $$
Like $\mathrm{And}$, is there another way to define $\mathrm{Or}$?
$x$ | $y$ | $\mathrm{Xor}\ x y$ |
---|---|---|
T | T | F |
T | F | T |
F | T | T |
F | F | F |
As the definition of xor, when two inputs are the same, it returns true; otherwise it’s false.
- If $x$ is true, then $\mathrm{Xor}\ xy = \mathrm{Not}\ y$;
- If $x$ is false, then $\mathrm{Xor}\ xy = y$.
$$ \mathrm{Xor} = \lambda xy. x\ (\mathrm{Not}\ y) y $$ This also the $\neq$ operator.
In conclusion, when defining binary boolean functions, we use the first input as a selector.
How to define $\equiv$ the beq
operator using lambda calculus?
Numerals
For any language to be useful in programming, it needs numbers. But lambda calculus is just a notation system of function, There is no register nor memory, how can we have number in such a system? As part of Churching Encoding, we can use function to define number system using functions.
The key idea is let the number represent function application, for example, $1$ is just apply some function once, $$ \mathcal{1} = \lambda fx. fx $$ Then $2$ is just $$ \mathcal{2} = \lambda fx. f(fx) $$ and so one. Then what is zero $0$, a function that takes two input and just return the second one without doing anything. $$ \mathcal{0} = \lambda fx. x = KI = F $$ which is just the Kite! In this way, 0 in lambda calculus also means false.
How do we define all the natural numbers? It seems impossible to write definitions like this forever. Recall the Peano axioms, especially the definition of Peano numbers.
Peano Axiom(first two):
- 0 is a natural number.
- For every natural $n$, its successor $n++$ is also a natural number (closure).
The key to define all natural numbers and addition is the successor, let $\mathrm{Succ} n$ denote the successor of $n$.
As the axiom says, $$ \begin{align} \mathcal{1} & = \mathrm{Succ}\ \mathcal{0} \\ \mathcal{2} & = \mathrm{Succ}\ \mathcal{1} \\ \mathcal{3} & = \mathrm{Succ}\ \mathcal{2} \\ & \vdots \end{align}$$
Then the only question is how do we define the successor function. $$ \begin{align} \mathcal{1} & = \mathrm{Succ}\ \mathcal{0} \\ \lambda fx. fx & = \mathrm{Succ}\ \lambda fx. x \ \end{align}$$ then we can define $\mathrm{Succ}$ to take a number (Church numeral) and the function $f$ to apply on it. $$ \mathrm{Succ} = \lambda nfx. f(nfx) $$ Then we can verify that $$ \begin{align} \mathrm{Succ}\ \mathcal{0} & = \lambda nfx. f(nfx) \ \mathcal{0} \\ & = \lambda fx . f(\mathcal{0}fx) \\ & = \lambda fx . fx \\ & = \mathcal{1}. \end{align}$$
Then to prove $\mathrm{Succ}$ works for all Church numeral is trivial. Thus, we have a way to define Peano numbers in lambda calculus!
Can we define $\mathrm{Succ}$ with the birds combinator we already seen?
We also define arithmetic! In the field of natural numbers, isn’t $\mathrm{Succ}\ n = n + 1$? What about general addition? As we learned from childhood, adding $x$ to $y$ is just add $1$ to $y$ for $x$ times, $$ \mathrm{Add} = \lambda xy . x\ \mathrm{Succ}\ y $$
If we do addition many times, we are doing multiplications. So we define multiplication as $$ \mathrm{Mult} = \lambda xyf. x(yf) = B $$ which is the composition Bluebird!
Can we define $\mathrm{Mult}$ as what we did for $\mathrm{Add}$?
As we defined successor, how can we have the presuccessor function? Can the presuccessor function $\mathrm{PreSucc}$ lead us to subtraction $\mathrm{Subs}$?
“Data Structure”
On the way to a finite-state machine?
Two fundamental data structures in programming are pairs and lists. And in functional programming, lists are defined with sets.
I still don’t understand why Java does not provide pair.
What is a pair?
A pair by definition is a storage of two values, like (a,b)
.
Then let us define a lambda expression that hold two values.
We also want some function to act of the pair,
so our pair would need a $f$ as input.
$$ \mathrm{Pair} = \lambda xyf. fxy $$
in Haskell syntax it is just (x,y)
.
Then we want a function to access these two values. That is,
- $\mathrm{Fst}$ that takes a pair and return its first value.
- $\mathrm{Snd}$ that takes a pair and return its second value.
Wait, isn’t this familiar? We already have Kestrel and Kite who take two values and return the first(second)! Then, we only need to apply Kestrel and Kite on the pair $$ \begin{align} \mathrm{Fst} & = \lambda p. pK \\ \mathrm{Snd} & = \lambda p. p(KI) \end{align} $$
For example, it evaluates as $$ \begin{align} \mathrm{Fst}(1,2) & = \lambda (1,2). (1,2)K = K\ 1\ 2 = 1 \\ \mathrm{Snd}(1,2) & = \lambda (1,2). (1,2)(KI) = KI\ 1\ 2 = 2. \end{align} $$
In Haskell, these two functions are defined as
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With pair defined, we can define list easily. In a functional language, list is not a sequential list in memory (of course there is no memory lol).
In functional languages, list is defined as either
- nil, or empty
- a pair of (item, list)
Let’s talk a look at how Haskell define a list
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In the Haskell,
a list is defined as a set of numbers with some order,
and a function (morphism) defined on each pair of them.
In this case []
is the accumulator.
In functional programming, given any list,we can replace its accumulator and morphism defined on it,then get a new list defined with the new morphism and new accumulator.This way of list action is called fold.
Thus, to define out list in lambda calculus, $$ \mathrm{List} = \lambda ilf. fil $$ where $i$ is the item, $l$ is the list.
Then its trivial to define the two most used function on list,
head
and tail
.
head
takes a list and returns its first element, i.e. theitem
$i$.tail
takes a list and returns its second to last elements as a list, i.e. $l$.
$$ \begin{align} \mathrm{Head} & = \lambda l. lK \\ \mathrm{Tail} & = \lambda l. l(KI) \end{align} $$
In Haskell, they are defined as
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Recursion or “Loop”
As it was defined, there is no recursion in lambda calculus. But we need recursion for a programming language to be useful, so Haskell Curry introduced the Y combinator (Fixed-point combinator).
Recall the Mockingbird. $$ M = \lambda f. ff $$ we said it is the self-application bird. The Y combinator uses the self-application to achieve recursion $$ Y = \lambda f. (\lambda x. fMx) (\lambda x. fMx) = \lambda f. (\lambda x. f(xx)) (\lambda x. f(xx))$$
If we apply $\beta$-reduction on the Y combinator with some input, $$ \begin{align} Y\ g & = \lambda f. (\lambda x. f(xx)) (\lambda x. f(xx)) g \\ & = (\lambda x. g(xx)) (\lambda x. g(xx)) \\ & = g\ ((\lambda x. g(xx)) (\lambda x. g(xx))) \\ & = g\ (\ldots g\ ((\lambda x. g(xx)) (\lambda x. g(xx))) \ldots) \end{align} $$ it is looping!
In imperative programming, we would normally avoid using recursion because calling functions requires spaces in stack, whereas loop is constant in space.
To avoid extra costs in space, functional programming uses tail call optimization (TCO) that allows tail recursion to run in constant space.
Therefore, when writing function programs, try to use tail recursion as possible.
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